0=4.9t^2+22t+5.5

Solution for 0=4.9t^2+22t+5.5 equation:

0=4.9t^2+22t+5.5

We move all terms to the left:

0-(4.9t^2+22t+5.5)=0

We add all the numbers together, and all the variables

-(4.9t^2+22t+5.5)=0

We get rid of parentheses

-4.9t^2-22t-5.5=0

a = -4.9; b = -22; c = -5.5;
Δ = b2-4ac
Δ = -222-4·(-4.9)·(-5.5)
Δ = 376.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-\sqrt{376.2}}{2*-4.9}=\frac{22-\sqrt{376.2}}{-9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+\sqrt{376.2}}{2*-4.9}=\frac{22+\sqrt{376.2}}{-9.8}
$